On a lathe project I want to cut and angle from 1.100" dia to 2.735" dia, over a 1" distance. I need to know the angle to set the compound to. The way I calculated this is to create an imaginary triangle between the 2.735" and 1.1" diameters, across the 1" distance. This led me to first subtract the small diameter from the equation because it it outside of the imaginary triangle.
2.735 = 1.100 = 2.635"
Now I plugged in the values to a triangle calculator at https://www.calculator.net/triangle-calculator.html.
It gave me 31.451 and 58.549° . I have set the compound to either of those angles but it is not meeting those two diameters over a 1" distance. Not sure what I am doing wrong.
Part is 2" long, and I am trying to have a single angle going from 2.735" to 1.100" in the middle 1" of the part, having .5" of 2.735 dia and .5" of 1.1" dia on either end. This is for a hand knob. The large end of the angle is at the correct location, linearly, and the small end is 1.100", for .5" in length. The black line is the 2" mark, from the end.
A pic of the part, currently.
Thanks,
Chris
2.735 = 1.100 = 2.635"
Now I plugged in the values to a triangle calculator at https://www.calculator.net/triangle-calculator.html.
It gave me 31.451 and 58.549° . I have set the compound to either of those angles but it is not meeting those two diameters over a 1" distance. Not sure what I am doing wrong.
Part is 2" long, and I am trying to have a single angle going from 2.735" to 1.100" in the middle 1" of the part, having .5" of 2.735 dia and .5" of 1.1" dia on either end. This is for a hand knob. The large end of the angle is at the correct location, linearly, and the small end is 1.100", for .5" in length. The black line is the 2" mark, from the end.
A pic of the part, currently.
Thanks,
Chris