I am brainstorming on making a 127 tooth gear. I'm looking at the destructions for the dividing head. The example there is for a 17 tooth gear with a 17 hole dividing circle and a 90 to 1 gear ratio tool. They show you to divide 90 by 17, coming up with an answer of 5 with a remainder of 5/17ths. That would be 5 turns plus 5 holes on the sector arms of the 17 hole dividing circle. That's all hunky dory, but my number is bigger than the 90 from the gear ratio. My thoughts are to mill a 127 hole dividing plate, mount it up to the head and do the math to make it work. When I divide 90 by 127, I come up with .7086614. I'm just not sure how to turn that number into a holes in the sector arm number. Remember the gear ratio of your tool is pretty irrelevant. If it is 40 to 1, show me the math for say a 47 tooth gear with a 47 hole dividing circle with your 40 to 1 tool. I hope that makes sense. If someone can illuminate this for me with one example, I can bend it to my will from there. Thanks ahead, Lee.