- Joined
- Feb 21, 2022
- Messages
- 772
With odd numbers of holes, one is always in the centre.
If the bar had a full radius on each end, then the end holes would be in the centre of the radius. The distance would be 1/2 the material width in from the end, I would also use this distance if the bar had square ends.
If the bar had a full radius on each end, then the end holes would be in the centre of the radius. The distance would be 1/2 the material width in from the end, I would also use this distance if the bar had square ends.