To recap the method I'm familiar with - I have a rotary table with a ratio of 90:1 and a collection of standard dividing plates and assuming for a moment, I want to divide a circle by 7, with a reduction of 90:1, I would divide 90 by 7, writing the remainder as a fraction. which in this case would be 12 and 6/7, multiplying the fraction by 7, we get 42 / 49. or, 12 turns on the wheel and 42 positions on a 49 hole dividing plate.
But what about a number of divisions that's much larger, in this case 359? as I understand it I would need a dividing plate that's a multiple of 359. Further looking at what I have, if we take the 1 degree and and divide it by 30 (30 degrees of hand wheel movement per degree on the table) you end up with .033 degrees of movement per degree on the hand wheel, which gives us 348.387 which doesn't work. Does anyone have any suggestions as to how to divide a circle in 359 even parts?
EDIT: I realize that 359 is prime. which means there will be no ratio that will perfectly divide the circle, but I'm looking for help to get close enough. One possible solution is to gash it very lightly, make a hob and hob the gear, if the size of the blank is correct I should end up with the required number of teeth. but anyway, I would appreciate your input.
Thanks!
But what about a number of divisions that's much larger, in this case 359? as I understand it I would need a dividing plate that's a multiple of 359. Further looking at what I have, if we take the 1 degree and and divide it by 30 (30 degrees of hand wheel movement per degree on the table) you end up with .033 degrees of movement per degree on the hand wheel, which gives us 348.387 which doesn't work. Does anyone have any suggestions as to how to divide a circle in 359 even parts?
EDIT: I realize that 359 is prime. which means there will be no ratio that will perfectly divide the circle, but I'm looking for help to get close enough. One possible solution is to gash it very lightly, make a hob and hob the gear, if the size of the blank is correct I should end up with the required number of teeth. but anyway, I would appreciate your input.
Thanks!
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