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- Nov 23, 2014
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- 2,609
Your idea is plausible. There's some math below.
There's (I think) a replacement Atlas 10"/12" lathe spindle on eBay right now for $110 plus reasonable shipping. It also comes with a set of replacement bearings and a MT3/MT2 adapter. Maybe pick it up "just in case" your project runs afoul? Having a back up means if you want to go through with it, you could go a little deeper knowing you'll be back up and running in a short time.
Contemplating my naval lint thinking about your project, what would fail first if you thinned out the spindle? The tube should be mostly under a torsional load; belt pulley turning the spindle against the load of cutting (plus a little lateral load from belt tension). I'd think you'd start slipping the belt before you'd snap the spindle in torsion.
Maybe do a little experiment with a torque wrench? Stick a socket on the torque wrench and chuck the socket in the 3-jaw. Clamp the motor pulley so it doesn't rotate and pull on the torque wrench. I'm guessing one of your belts will slip at some point and measure that torque.
Or consider this though I had my strength of materials class before Ronald Regan even considered running for office!
Torsional stress = tau = (T x L) / (J x G)
T = torque
L = length of the rod
J = Polar moment of inertia
G = Modulus of rigidity
If you bore the spindle larger, the only thing you are changing is the polar moment of inertia which for a tube is (I did pull this from the web):
J = PI x (D^4 - d^4) / 32
Your "as designed" J is: 3.1415 x (2.441 - 0.372) / 32 = 0.203 in^4
If you opened up the bore to 1", your J is: 3.1415 x (2.441 - 1.0) / 32 = 0.1415 in^4
If you opened up the bore to 7/8", your J is: 3.1415 x (2.441 - 0.5862) / 32 = 0.1821 in^4
When plugged into the torsional stress formula, going to a 7/8" bore would raise the torsional stress for a given torque by ~10%. Going to a 1" bore raises it by ~30%. Frankly, seems plausible, but it's your lathe and I've forgotten a lot of this stuff due to inactivity!
Bruce
eBay item# 165620016595
There's (I think) a replacement Atlas 10"/12" lathe spindle on eBay right now for $110 plus reasonable shipping. It also comes with a set of replacement bearings and a MT3/MT2 adapter. Maybe pick it up "just in case" your project runs afoul? Having a back up means if you want to go through with it, you could go a little deeper knowing you'll be back up and running in a short time.
Contemplating my naval lint thinking about your project, what would fail first if you thinned out the spindle? The tube should be mostly under a torsional load; belt pulley turning the spindle against the load of cutting (plus a little lateral load from belt tension). I'd think you'd start slipping the belt before you'd snap the spindle in torsion.
Maybe do a little experiment with a torque wrench? Stick a socket on the torque wrench and chuck the socket in the 3-jaw. Clamp the motor pulley so it doesn't rotate and pull on the torque wrench. I'm guessing one of your belts will slip at some point and measure that torque.
Or consider this though I had my strength of materials class before Ronald Regan even considered running for office!
Torsional stress = tau = (T x L) / (J x G)
T = torque
L = length of the rod
J = Polar moment of inertia
G = Modulus of rigidity
If you bore the spindle larger, the only thing you are changing is the polar moment of inertia which for a tube is (I did pull this from the web):
J = PI x (D^4 - d^4) / 32
Your "as designed" J is: 3.1415 x (2.441 - 0.372) / 32 = 0.203 in^4
If you opened up the bore to 1", your J is: 3.1415 x (2.441 - 1.0) / 32 = 0.1415 in^4
If you opened up the bore to 7/8", your J is: 3.1415 x (2.441 - 0.5862) / 32 = 0.1821 in^4
When plugged into the torsional stress formula, going to a 7/8" bore would raise the torsional stress for a given torque by ~10%. Going to a 1" bore raises it by ~30%. Frankly, seems plausible, but it's your lathe and I've forgotten a lot of this stuff due to inactivity!
Bruce
eBay item# 165620016595